6x-25x^2+23x-6=0

Solution for 6x-25x^2+23x-6=0 equation:

6x-25x^2+23x-6=0

We add all the numbers together, and all the variables

-25x^2+29x-6=0

a = -25; b = 29; c = -6;
Δ = b2-4ac
Δ = 292-4·(-25)·(-6)
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{241}}{2*-25}=\frac{-29-\sqrt{241}}{-50}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{241}}{2*-25}=\frac{-29+\sqrt{241}}{-50}
$